9-4sin^2x=4cos^2+5

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Solution for 9-4sin^2x=4cos^2+5 equation:


Simplifying
9 + -4sin2x = 4cos2 + 5

Reorder the terms:
9 + -4in2sx = 5 + 4cos2

Solving
9 + -4in2sx = 5 + 4cos2

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -4in2sx = 5 + -9 + 4cos2

Combine like terms: 9 + -9 = 0
0 + -4in2sx = 5 + -9 + 4cos2
-4in2sx = 5 + -9 + 4cos2

Combine like terms: 5 + -9 = -4
-4in2sx = -4 + 4cos2

Divide each side by '-4n2sx'.
i = n-2s-1x-1 + -1cn-2osx-1

Simplifying
i = n-2s-1x-1 + -1cn-2osx-1

Reorder the terms:
i = -1cn-2osx-1 + n-2s-1x-1

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